Codility: BinaryGap Solution

1function solution(N) {
2  let tempN = N
3  let max = 0
4  let curr = 0
5  let numOfOne = 0
6  while (tempN > 0) {
7    let rmd = Math.floor(tempN % 2)
8    if (rmd === 1) {
9      numOfOne += 1
10      if (numOfOne === 2) {
11        if (curr > max) {
12          max = curr
13        }
14
15        // reset
16        numOfOne = 1
17        curr = 0
18      }
19    } else if (rmd === 0 && numOfOne === 1) {
20      curr += 1
21    }
22    tempN = Math.floor(tempN / 2)
23  }
24  return max
25}