LeetCode: Single Number Solution

Count occurence of each element

Approach

Use a hash table (Map) to store key-value pairs of number and its occurence

Implementation

1var singleNumber = function (nums) {
2 const numOccMap = nums.reduce(
3 (acc, el) => acc.set(el, (acc.get(el) || 0) + 1),
4 new Map()
5 )
6
7 for (const [num, occ] of numOccMap) {
8 if (occ === 1) {
9 return num
10 }
11 }
12}

References

Original problem

MDN Map()

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Tags

leetcode

hash table

bit manipulation

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