LeetCode: How Many Numbers Are Smaller Than The Current Number Solution

1var smallerNumbersThanCurrent = function (nums) {
2  const N = nums.length
3  const res = []
4  for (let i = 0; i < N; i++) {
5    let count = 0
6    for (let j = 0; j < N; j++) {
7      if (i !== j && nums[j] < nums[i]) {
8        count++
9      }
10    }
11    res.push(count)
12  }
13  return res
14}