LeetCode: Count Number Of Homogenous Substrings Solution
Approach
Accumulated count for contiguous substring of the same characters
1"a" -> 1 (1)2"aa" -> 3 (1 + 2)3"aaa" -> 6 (1 + 2 + 3)
Implementation
1/**2 * @param {string} s3 * @return {number}4 */5var countHomogenous = function (s) {6 let res = 0,7 prev = "",8 acc9 for (const c of s) {10 acc = c === prev ? acc + 1 : 111 prev = c12 res += acc13 }14 return res % (1e9 + 7)15}
Comments
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Tags
leetcode
string
greedy
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