LeetCode: Summary Ranges Solution
Straight forward checkingApproach
On each iteration, init start
and end
to be equal to the iterated element
Keep assigning end
while next element is greater than the current by one unit
If start !== end
then it's a sub range
Implementation
1var summaryRanges = function (nums) {2 let start, end3 let res = []45 for (let i = 0; i < nums.length; i++) {6 start = end = nums[i]78 for (; nums[i + 1] === nums[i] + 1; i++) {9 end = nums[i + 1]10 }1112 res.push(start === end ? "" + start : start + "->" + end)13 }1415 return res16}
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Tags
leetcode
array
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Boyer-Moore Voting Algorithm