LeetCode: Partition Array into Disjoint Intervals Solution
ReasoningApproach
LeetCode's official solution covered well
Implementation
1/**2 * @param {number[]} nums3 * @return {number}4 */5var partitionDisjoint = function (nums) {6 const [prefixMax, postfixMin] = [[], []]7 let [max, min] = [nums[0], nums.slice(-1)[0]]89 for (const num of nums) {10 max = Math.max(max, num)11 prefixMax.push(max)12 }1314 for (const num of [...nums].reverse()) {15 min = Math.min(min, num)16 postfixMin.push(min)17 }18 postfixMin.reverse()1920 for (let i = 0; i < nums.length - 1; i++) {21 if (prefixMax[i] <= postfixMin[i + 1]) {22 return i + 123 }24 }2526 return 027}
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Tags
leetcode
array
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